3x^2+3y^2-3x-3y-5=0

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Solution for 3x^2+3y^2-3x-3y-5=0 equation: 


Simplifying
3x2 + 3y2 + -3x + -3y + -5 = 0

Reorder the terms:
-5 + -3x + 3x2 + -3y + 3y2 = 0

Solving
-5 + -3x + 3x2 + -3y + 3y2 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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